146=0.00012x^2

Solution for 146=0.00012x^2 equation:

146=0.00012x^2

We move all terms to the left:

146-(0.00012x^2)=0

We get rid of parentheses

-0.00012x^2+146=0

a = -0.00012; b = 0; c = +146;
Δ = b2-4ac
Δ = 02-4·(-0.00012)·146
Δ = 0.07008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.07008}}{2*-0.00012}=\frac{0-\sqrt{0.07008}}{-0.00024}
=-\frac{\sqrt{}}{-0.00024}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.07008}}{2*-0.00012}=\frac{0+\sqrt{0.07008}}{-0.00024}
=\frac{\sqrt{}}{-0.00024}
$